4n^2-19n+21=

Solution for 4n^2-19n+21= equation:

Simplifying
4n2 + -19n + 21 = 0

Reorder the terms:
21 + -19n + 4n2 = 0

Solving
21 + -19n + 4n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(7 + -4n)(3 + -1n) = 0

Subproblem 1
Set the factor '(7 + -4n)' equal to zero and attempt to solve:

Simplifying
7 + -4n = 0

Solving
7 + -4n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -4n = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -4n = 0 + -7
-4n = 0 + -7

Combine like terms: 0 + -7 = -7
-4n = -7

Divide each side by '-4'.
n = 1.75

Simplifying
n = 1.75
Subproblem 2
Set the factor '(3 + -1n)' equal to zero and attempt to solve:

Simplifying
3 + -1n = 0

Solving
3 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1n = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1n = 0 + -3
-1n = 0 + -3

Combine like terms: 0 + -3 = -3
-1n = -3

Divide each side by '-1'.
n = 3

Simplifying
n = 3
Solution
n = {1.75, 3}